Marso1
@marso1
Student
Joined: March 20, 2021 8:41 am
Last seen: September 14, 2021 8:38 pm
Topics: 5 / Replies: 10
Reply
RE: How to reduce oscillations in a graphic

Hi@negativevolume Do not worry! Many thanks for your suggestion. Regards Marso1

3 years ago
Reply
RE: How to reduce oscillations in a graphic

Hi @negativevolume Many thanks for your help. My simulation is implicit at first, then it switches to explicit. I am using quad element with 4 ...

3 years ago
Topic
Replies: 5
Views: 1348
Reply
RE: Distorted Mesh

Hi @negativevolume !!! Many thanks for your help. I read the instructions in the post which you suggested, As the bar is straight, I used the fun...

3 years ago
Topic
3 years ago
Replies: 3
Views: 1245
Reply
RE: Difference between : off and disable

Hi @negativevolume Many thanks

3 years ago
Topic
Replies: 2
Views: 1197
Topic
3 years ago
Replies: 0
Views: 909
Reply
RE: The damper

@negativevolume Hi! I finally solved the problem was in a curve, I forgot to put "SIDR" equal to zero. Many thanks Regards Marso1

3 years ago
Reply
RE: The damper

@negativevolume. The distance between the damper down and the bar is zero. (It must be so) The distance between the damper up and the bar is 1 mm

3 years ago
Reply
RE: The damper

@negativevolume Yes I have. Under the properties i put the shell thiknes (T1=2mm) Under the groups I put both (MST and SST) = 0 Regards  ...

3 years ago
Reply
RE: The damper

@negativevolume, I did It, At first the force curve is a ramp and than is constant. The force is "Load Node" The contact between the bar and ...

3 years ago
Reply
RE: The damper

Hi@samuelbas The curve that I am using to define the force last for une second, but the test last 0.005 seconds. I have to find the force that sto...

3 years ago
Reply
RE: The damper

Hi,@negativevolume. Thanks for your help. The damper down is fixed and the damper up has to sqeeze the bar. On the damper up a force is applied....

3 years ago
Topic
3 years ago
Replies: 13
Views: 975